8e^2=17

Solution for 8e^2=17 equation:

8e^2=17

We move all terms to the left:

8e^2-(17)=0

a = 8; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·8·(-17)
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{34}}{2*8}=\frac{0-4\sqrt{34}}{16}
=-\frac{4\sqrt{34}}{16}
=-\frac{\sqrt{34}}{4}
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{34}}{2*8}=\frac{0+4\sqrt{34}}{16}
=\frac{4\sqrt{34}}{16}
=\frac{\sqrt{34}}{4}
$